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Probability Density Function Calculator

PDF Calculator

Calculate Probability Density Function (PDF) values for continuous distributions with step-by-step solutions and graphical visualizations.

f(x) = (1/√(2πσ²)) e^(-(x-μ)²/(2σ²))
Normal
Exponential
Uniform
Custom

Normal Distribution N(μ, σ²)

PDF gives relative likelihood at a point. Area under PDF curve = 1. For probabilities, use CDF.

Standard Normal

μ=0, σ=1, x=0
f(0) = 0.3989

Exponential λ=1

λ=1, x=1
f(1) = 0.3679

Uniform [0,1]

a=0, b=1, x=0.5
f(0.5) = 1.0000

Normal μ=10, σ=2

μ=10, σ=2, x=10
f(10) = 0.1995

PDF Calculation Result

0.3989

Distribution
Normal
X value
0.000
PDF f(x)
0.3989

PDF Calculation:

PDF Visualization:

Distribution Properties:

PDF Interpretation:

Probability Density Function (PDF) gives the relative likelihood of a continuous random variable at a specific point.

What is Probability Density Function (PDF)?

Probability Density Function (PDF) is a function that describes the relative likelihood for a continuous random variable to take on a given value. Unlike probability mass functions for discrete variables, PDF gives density rather than probability at a point. The probability of the variable falling within a particular range is given by the integral of the PDF over that range, with the total area under the PDF curve always equal to 1.

Common PDF Formulas

Normal Distribution

f(x) = (1/√(2πσ²)) e^(-(x-μ)²/(2σ²))

Bell curve

Most common

Exponential Distribution

f(x) = λe^(-λx) for x≥0

Memoryless

Waiting times

Uniform Distribution

f(x) = 1/(b-a) for a≤x≤b

Constant density

Equal likelihood

Properties

∫f(x)dx = 1, f(x) ≥ 0

Total area = 1

Non-negative

Key PDF Formulas and Properties

1. Normal (Gaussian) Distribution

f(x) = (1/√(2πσ²)) × e-(x-μ)²/(2σ²)

Where:
μ = mean (center of distribution)
σ = standard deviation (spread)
σ² = variance
Domain: -∞ < x < ∞

2. Exponential Distribution

f(x) = λe-λx for x ≥ 0
f(x) = 0 for x < 0
Mean: 1/λ, Variance: 1/λ²
Memoryless property: P(X > s+t | X > s) = P(X > t)

3. Uniform Distribution

Property Formula Interpretation Example [0,1]
PDF f(x) = 1/(b-a) for a≤x≤b Constant density f(x) = 1
Mean μ = (a+b)/2 Center point 0.5
Variance σ² = (b-a)²/12 Spread measure 1/12 ≈ 0.0833
CDF F(x) = (x-a)/(b-a) Cumulative probability F(x) = x

Real-World Applications

Statistics & Data Science

  • Statistical Modeling: Fitting distributions to data
  • Hypothesis Testing: Calculating p-values and test statistics
  • Maximum Likelihood Estimation: Parameter estimation using PDFs
  • Bayesian Statistics: Prior and posterior distributions

Engineering & Physics

  • Signal Processing: Noise modeling and analysis
  • Reliability Engineering: Failure time distributions
  • Quantum Mechanics: Wave function probability densities
  • Thermodynamics: Molecular speed distributions

Finance & Economics

  • Risk Management: Modeling asset returns and losses
  • Option Pricing: Black-Scholes model assumptions
  • Economic Forecasting: Probability distributions of economic variables
  • Actuarial Science: Insurance claim distributions

Machine Learning & AI

  • Generative Models: Learning data distributions
  • Anomaly Detection: Identifying outliers using PDFs
  • Bayesian Networks: Probabilistic graphical models
  • Reinforcement Learning: Policy gradient methods

Common PDF Examples and Values

Distribution Parameters X value PDF f(x) Interpretation
Standard Normal μ=0, σ=1 0 0.3989 Highest point (mode)
Standard Normal μ=0, σ=1 1 0.2420 1 standard deviation from mean
Exponential λ=1 0 1.0000 Maximum value
Exponential λ=1 1 0.3679 Mean waiting time
Uniform [0,1] 0.5 1.0000 Constant throughout interval
Normal μ=100, σ=15 100 0.0266 IQ distribution mean

Step-by-Step PDF Calculation Process

Example 1: Standard Normal PDF at x=0

  1. Parameters: μ = 0, σ = 1, σ² = 1
  2. PDF formula: f(x) = (1/√(2πσ²)) × e^(-(x-μ)²/(2σ²))
  3. Substitute values: f(0) = (1/√(2π×1)) × e^(-(0-0)²/(2×1))
  4. Simplify exponent: (0-0)² = 0, so e^0 = 1
  5. Calculate constant: 1/√(2π) ≈ 1/2.5066 ≈ 0.3989
  6. Final result: f(0) = 0.3989
  7. Interpretation: At the mean, standard normal PDF has its maximum value

Example 2: Exponential PDF (λ=1) at x=1

  1. Parameters: λ = 1, x = 1
  2. PDF formula: f(x) = λe^(-λx) for x ≥ 0
  3. Substitute values: f(1) = 1 × e^(-1×1) = e^(-1)
  4. Calculate: e^(-1) ≈ 0.3679
  5. Interpretation: Probability density at the mean waiting time (1/λ = 1)
  6. Note: Area under curve from 0 to ∞ equals 1

Related Calculators

Frequently Asked Questions (FAQs)

Q: What's the difference between PDF and probability?

A: PDF gives density at a point, not probability. For continuous variables, probability at a single point is zero. Probability over an interval [a,b] is ∫[a,b] f(x)dx. PDF values can be greater than 1, but the area under the entire curve always equals 1.

Q: Can PDF values be greater than 1?

A: Yes, PDF values can be greater than 1. What matters is that the total area under the PDF curve equals 1. For example, a uniform distribution on [0, 0.1] has PDF = 10 for all x in [0, 0.1], but area = 10 × 0.1 = 1.

Q: How do I convert PDF to probability?

A: To get probability P(a ≤ X ≤ b), integrate the PDF from a to b: P = ∫[a,b] f(x)dx. For the normal distribution, this requires numerical integration or using the CDF (cumulative distribution function).

Q: What is the relationship between PDF and CDF?

A: CDF F(x) = P(X ≤ x) = ∫[-∞,x] f(t)dt. PDF is the derivative of CDF: f(x) = dF(x)/dx. CDF gives probabilities, PDF gives density rates of change.

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